The Big Ten champion Ohio State Buckeyes now know where they will continue their chase for the national title.
Sunday, the College Football Playoff committee gave the Buckeyes the No. 2 seed.
OSU will face No. 3 Clemson in the 2019 Fiesta Bowl.
The game will be played Sunday, December 28 in Glendale, Ariz.
The Buckeyes opened as a 1-point favorite.
Ohio State earned its spot with a perfect 13-0 record and their third consecutive outright Big Ten championship. They beat Wisconsin, 34-21 in Indianapolis on Saturday night.
Clemson also finished 13-0, as the ACC champion. The Tigers destroyed Virginia, 62-17 to win that title.
This will be the fourth meeting between the Buckeyes and Tigers in the schools’ history. Clemson has won each of the previous three meetings, including the 1978 Gator Bowl, the 2014 Orange Bowl, and the 2016 Fiesta Bowl.
No. 1 LSU and No. 4 Oklahoma will face off in the Peach Bowl in the other semifinal.
Ohio State head coach Ryan Day and a handful of Buckeyes will hold a press conference shortly to discuss the news.
#CFBPlayoff Semifinal at the @Fiesta_Bowl.
2️⃣. Ohio State // @OhioStateFB
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3️⃣. Clemson // @ClemsonFBSaturday, December 28. Who’s in? ??#GoBucks // #AllIn pic.twitter.com/e8h2GCxoID
— College Football Playoff (@CFBPlayoff) December 8, 2019
GAME ON: @OhioStateFB and @ClemsonFB are coming to Arizona for a rematch in the 2019 @PlayStation #FiestaBowl and @CFBPlayoff Semifinal! ???
Get your tickets NOW: https://t.co/IujKyBpyDc#GreatnessAwaits | #ToughLove | #ALLIN pic.twitter.com/MCJxDy0yKG
— Fiesta Bowl (@Fiesta_Bowl) December 8, 2019